Fission of U-235 nucleus releases 200 MeV energy. Calculate the fission rate (i.e.,no. Of fissions per second ) in order to produce a power of 320 MW.

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

200 Mev energy is released when one nucleus of .^235U undergoes fission. Find the number of fissions per second required for producing a power of 1 mega watt.

The energy released by the fission of a single uranium nucleus is 200 MeV. The number of fission of uranium nucleus per second required to produce 16 MW of power is (Assume efficiency of the reactor is 50%)

The energy released by the fission of a single uranium nucleus is 200 MeV . The number of fission of uranium nucleus per second required to produce 16 MW of power is (Assume efficiency of the reactor is 50% )

If 200 MeV energy is released in the fission of a single nucleus of ._(92)U^(235) , how many fissions must occur per sec to produce a power of 1 kW?

Assuming the splitting of U^235 nucleus liberates 200 MeV energy, find (a) the energy liberated in the fission of 1 kg of U^235 and (b) the mass of the coal with calorific value of 30 kJ//g which is equivalent to 1 kg of U^235 .

Energy released in the fission of a single ._92 U^235 nucleus is 200 MeV . The fission rate of a ._92 U^235 fuelled reactor operating at a power level of 5 W is.

Assuming that 200MeV of energy is released per fission of uranium ato, find the number of fission per second required to release one kilowatt power.

If 200 MeV energy is released in the fission of a single U^235 nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given 1 eV = 1.6 xx 10^-19 J ).

If 200 MeV energy is released in the fission of a single U^235 nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given 1 eV = 1.6 xx 10^-19 J ).