Draw a circuit diagram for the determination of the internal resistance of a cell using potentiometer. Derive the formula to be used.

Internal resistance of a cell depends on

For the given circuit, If internal resistance of cell is 1.5 Omega , then

Draw a labelled circuit diagram of a potentiometer to measure internal resistance of a cell. Write the working formula. (Derivation not required).

Describe the method of determination of surface tension of a liquid by capillary rise. Derive the formula used.

Figure 6.13 shows a 2.0 V potentiometer used for the determination of internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 76.3 cm . Whan a resistor of 9.5 Omega is used in the external circuit of the cell, the balance point shifts to 64.8 cm , length of the potentiometer. Dentermine the internal resistance of the cell.

Draw a diagram of the internal structure of the human ovary.

3V poteniometer used for the determination of internal resistance of a 2.4V cell. The balanced point of the cell in open circuit is 75.8cm. When a resistor of 10.2Omega is used in the external circuit of the cell the balance point shifts to 68.3cm length of the potentiometer wire. The internal resistance of the cell is

In an experiment to determine the internal resistance of a cell with potentiometer, the balancing length is 165 cm. When a resistance of 5 ohm is joined in parallel with the cell the balancing length is 150 cm. The internal resistance of cell is

Draw a diagram to illustrate the determination of the focal length of a convex lens using an auxiliary plane mirror.

A potentiometer can be used to measure