For the complex ion of `[Fe(CN)_6]^(3-)` :
State its magnetic property.

Explanation

To determine the magnetic property of the complex ion \([Fe(CN)_6]^{3-}\), we will follow these steps:

### Step 1: Determine the oxidation state of Iron (Fe)
The complex ion is \([Fe(CN)_6]^{3-}\). The cyanide ion (CN) has a charge of -1. Since there are 6 cyanide ions, the total contribution from CN is:
\[ 6 \times (-1) = -6 \]
Let the oxidation state of Fe be \(x\). The overall charge of the complex is -3, so we can set up the equation:
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