When acetic acid is reacted with calcium hydroxide and the product is distilled dry, the i compound formed is :

Options

A. Calcium acetate
B. Acetone
C. Acetaldehyde
D. Acetic anhydride

Explanation

To solve the question regarding the reaction of acetic acid with calcium hydroxide and the product formed after dry distillation, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are acetic acid (CH₃COOH) and calcium hydroxide (Ca(OH)₂).

2. **Write the Reaction**:
When acetic acid reacts with calcium hydroxide, a neutralization reaction occurs, resulting in the formation of calcium acetate and water:
\[ 2 \text{CH}_3\text{COOH} + \text{Ca(OH)}_2 \rightarrow \text{Ca(CH}_3\text{COO)}_2 + 2 \text{H}_2\text{O} \]
Here, calcium acetate (Ca(CH₃COO)₂) is formed along with water.

3. **Distillation Process**:
The question mentions that the product is distilled dry. Dry distillation typically involves heating the product to remove water and other volatile components.

4. **Dry Distillation of Calcium Acetate**:
When calcium acetate is subjected to dry distillation, it decomposes to form acetone (CH₃COCH₃) and calcium carbonate (CaCO₃):
\[ \text{Ca(CH}_3\text{COO)}_2 \xrightarrow{\text{heat}} \text{CH}_3\text{COCH}_3 + \text{CaCO}_3 \]

5. **Identify the Final Product**:
The main compound formed after the dry distillation of calcium acetate is acetone (CH₃COCH₃).

### Final Answer:
The compound formed when acetic acid is reacted with calcium hydroxide and the product is distilled dry is **acetone (CH₃COCH₃)**.

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