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Calculate the maximum work that can be o...

Calculate the maximum work that can be obtained from the given electrochemical cell constructed with two metals M and N.
`[E_(M^(2+)//M)^(Theta)= -0.76V, E_(N^(2+)//N)^(Theta) = 0.34V]`

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Verified by Experts

According to given cell reaction
`E_("anode" (M^(+2)//M))^@ = – 0*76V`
`E_("cathode" (N^(+2)//N))^@ = + 0*34 V`
`n = 2`
Now, `W_("electrical") = - n FE_(cell)^@`
`= - 2 xx 96500xx[0*34-(-0*76)]`
`= -2xx 96500 x× 1*1`
`=-212*3 k` joule.
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