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In a first order reaction, 10% of the re...

In a first order reaction, 10% of the reactant is consumed in 25 minuts. Calculate:
The half life of the reaction.

Text Solution

Verified by Experts

For first order reaction,
`K = (2*303)/t log "" a/(a-x)`
`=(2*303)/25 log" 100/(100-10)`
`= 0*0042145`
`:. " Half life, " T = (0*693)/K`
`=(0*693)/(0*0042145)`
`T = 164*43` minutes.
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