A hot solid of mass 60 g at `100^(@)C` is placed in 150 g of water at `20^(@)C`. The final steady temperature recorded is `25^(@)C`. Calculate the specific heat capacity of the solid. [Specific heat capacity of water = 4200 `kg^(-1)""^(@)C^(-1)`]

Explanation

To find the specific heat capacity of the solid, we can use the principle of calorimetry, which states that the heat lost by the hot solid will be equal to the heat gained by the water.

### Step-by-Step Solution:

1. **Identify the known values:**
- Mass of the solid, \( m_1 = 60 \, \text{g} \)
- Initial temperature of the solid, \( T_1 = 100 \, \text{°C} \)
- Mass of the water, \( m_2 = 150 \, \text{g} \)
...