`C_3H_8` + `O_2` rarr `CO_2` + `H_2 O` రసాయన సమీకరణాలు తుల్యం చేయండి

2C_2 H_6 + 7O_2 rarr 4CO_2 + 6H_2O + energy .This is……type of reaction.

2C_((s)) + 1/2O_(2(gg) rarr CO_(2(g)) , DeltaH = -787 KJ H_(2(g)) + 1/2O_(2(g)) rarr H_2O_((l)) , DeltaH = -286 KJ C_2H_(2(g)) + 2 1/2O_(2(g)) rarr 2CO_(2(g)) + H_2O_((l)) , DeltaH = -1301 KJ . Heat of formation of acetylene in KJ is

Given that CH_3CHO + 5/2O_2 rarr 2CO_2 + 2H_2O, DeltaH = -1168 KJ//"mole" CH_3COOH + 2O_2 rarr 2CO_2 + 2H_2O, Delta H = -876 KJ//"mole" DeltaH for the reaction CH_3CHO + 1/2O_2 rarr CH_2COOH in KJ//mol is

C_(2)H_(6(g)) + 3.5 O_(2(g)) rarr 2CO_(2(g)) + 3H_(2)O_((g)) Delta S_("vap") (H_(2)O,l) = x_(1) " cal" K^(-1) (boiling point is T_(1) ) Delta H_(f) (H_(2)O, l) = x_(2), Delta H_(f) (CO_(2)) = x_(3), Delta H_(f) (C_(2)H_(6)) = x_(4) Hence Delta H for the reaction is

H_2O+ ____ to H_3O^+

2C_(3)H_(8)+10O_(2)rarr 6CO_(2)+8H_(2)O Is it a balanced equation as per rules? How do you say?

Assertion (A) : 2C_(3)H_(8)+10O_(2)rarr 6CO_(2)+8H_(2)O is not a balanced equation. Reason (R) : The coefficients are not the smallest whole numbers.

Prasad wrote a balanced chemical equation as 2C_(3)H_(8)+10O_(2)rarr 6CO_(2)+8H_(2)O , but Pallavi argued it is not a balanced equation. Who is right ? Why ?

The following equilibria are given N_2+3H_2 harr 2NH_3 , K_c=K_1 , N_2+O_2 harr 2NO, k_c=K_2 , H_2+1/2 O_2 harr H_2O, K_C = K_3 The equilibrium constant of the reaction. 2NH_3+5/2 O_2 harr 2NO+3H_2O in the terms of K_1,K_2 and K_3 is

Let us assume the chemical equation 2C_(3)H_(8)+10O_(2)rarr 6CO_(2)+8H_(2)O a) Is is balaced equation as per rules ? b) How do you say?