Calculate the volume, mass and number of molecules of hydrogen liberated when 230 g of sodium reacts with excess of water at STP. (atomic masses of Na = 23U, O = 16U, and H = 1U)
the balanced equation for the above reaction is
`{:(2Na_((s))+2H_(2)O_((l)),,to2NaOH_((aq)) +H_(2(g))+H_(2(g))uparrow),((2xx23)U+ 2(2xx1 +1 xx 16)U,,to2(23+16+1)U+(2xx1)U),(46 U + 36U,,to80U + 2U),(or46g + 36g ,, to 80 g + 2 g):}`

Calculate the volume, mass and number of molecules of hydrogen liberated when 230 g of sodium reacts with excess of water at STP (atomic masses of Na = 23U, O = 16 U and H = 1U).

Molecular mass of HNO_3 (Atomic masses of H=1U, N=14U, O=16U)-

The value of Delta H - Delta U for the following reaction at 27^(@)C will be : N_(2(g)) + 3H_(2(g)) rarr 2NH_(3(g))

The enthalpy of the reaction H _(2 (g)) + 1/2 O _(2(g)) to H _(2) O _((g)) is Delta H _(1) and that of H _(2(g)) + 1/2 O _(2(g)) to H _(2) O _((l)) is Delta H _(2). Then

Calculate the amount of aluminium, required to get 1120 kg of iron from the given chemical equation. 2Al_((s))+Fe_(2)O_(3(s))rarrAl_(2)O_(3(s))+Fe_((s))" " (atomic mass of Al = 27U, Fe = 58U and O = 16 U)

Which has more number of atoms 100 g of sodium or 100 g of iron? Justify your answer. Atomic mass of sodium =23 u, atomic mass of iron= 56 u)

The distance travelled by a particle in n^(th) second is S_n =u+a/2 (2n-1) where u is the velocity and a is the acceleration. The equation is

Al_((s)) + fe_(2)O_(3(s)) to Al_(2) O_(3(s)) + Fe_((s)) (atomic masses of Al = 27U, Fe = 56U, and O = 16U) 2Al_((s)) +Fe_(2)O_(3(s)) to Al_(2)O_(3(s)) + 2Fe_((s)) , is a balanced equation. (2 xx 27)U + (2xx 56 + 3xx 16)U to (2xx 27 + 3 xx 16) U + (2 xx 56) U {:(54U+160U,,to102U+112U),(or2" mol" + "1 mol",,to 1"mol" + 2"mol"),(54g + 160g ,, to 102 g + 112 g):} Suppose that your asked to calculate the amount of aluminium, required to get 1120 kg of iron by the above reaction.

Calculate the binding energy of an alpha -particle. Given that mass of proton = 1.0073 u, mass of neutron = 1.0087 u, and mass of alpha - particle = 4.0015 u.