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Al((s))+Fe(2)O(3(s))rarrAl(2)O(3(s))+Fe(...

`Al_((s))+Fe_(2)O_(3(s))rarrAl_(2)O_(3(s))+Fe_((s))`
`54_((g))+160_(g)rarr 102g+112`
was given, Then, the amount of aluminium required to get 1120 grams of iron is

A

540 gr

B

540 kg

C

112 gr

D

1120 gr

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