Home
Class 10
CHEMISTRY
The first two members of alkene series i...

The first two members of alkene series is

A

Methene, ethene

B

Methane, ethane

C

Ethene, propene

D

Ethyne, propyne

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • ATOMS AND MOLECULES

    VGS PUBLICATION-BRILLIANT|Exercise OBJECTIVE TYPE QUESTION|87 Videos

  • CHEMICAL BONDING

    VGS PUBLICATION-BRILLIANT|Exercise EXERCISE|302 Videos

Similar Questions

Explore conceptually related problems

The wavelength of the first member of Lyman series is 1216 Å . Calculate the wavelength of second member of Balmer series.

The wavelength of the first member of the Balmer series in hydrogen spectrum is x Å. Then the wave length (in Å) of the first member of Lyman series in the same spectrum is

The wavelength of the first member of the Balmer series in hydrogen spectrum is xÅ . Then the wave length ("in "Å) of the first member of Lyman series in the same spectrum

The wavelength of first member of Balmer series is 6563 Å . Calculate the wavelength of second member of Lyman series.

If the wave length of the first member of Balmer series of a hydrogen atom is 6300Å, that of the second member will be nearly

The first member of homologous series among alkynes is____

Write the structures of different isomers corresponding to the 5^(th) member of alkyne series. Write their IUPAC names.

If the wavelength of first member of Balmer series of hydrogen spectrum is 6564 A^(@) . The wavelength of second member of Balmer series will be :

The second member of Lyman series in hydrogen spectrum has wavelength 5400 Å . Find the wavelength of first member.