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VGS PUBLICATION-BRILLIANT-EXPONENTS AND POWERS-EXERCISE
- (1/2016)^0=
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- The general form of 1.275 xx 10^3 is
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- The standard form of 23,40,00,000 is
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- (7^-1-18^-1)^0=
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- If we divide 8^5 bywe get 8.
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- 10^-3=
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- (1/2)^-2div(1/2)^-2=
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- (2 ^5div 2^6) xx 2=
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- 5^(3x-1)div25=125 then x=
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- 6^-2/6^n=6^-3 then n=
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- (5^mxx5^3xx5^-2)/5^-5=5^12 then m=
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- 2^10=
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- Which of the following is correct?
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- 3x^-1=
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- Express the following in the standard form : 4.67 xx 10^4
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- Simplify and give reason : (4^0+5^-1)xx5^2xx1/3
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- Simplify and give reason :1+2^-1+3^-1+4^0
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- 3^0-3^-1=
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- m= 3, n = 1 then m^n-n^m=
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- Find the value of 'n' in each of the following :7^(2n+1)div49=7^3
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