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VGS PUBLICATION-BRILLIANT-EXPONENTS AND POWERS-EXERCISE
- 3^0 +4^0-5^0-3^0=
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- -4^-1+8^-1div(2/3)^-1=
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- (-1/5)^-1=
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- (2/3)^-3=
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- 64^-(0.5)=
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- 1 + (9-10)^-5=
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- x=3 ^400, y=4^ 300 then
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- 64^(2//3)=
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- root(4)(81) యొక్క ఘాతరుపము
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- [((3)^2)^3]^4=
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- 2^4xx(32)^-1=
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- Base in 2x^-3 is
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- (125)^ (-2//3)=
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- Use differential to approximate (25)^((1)/(3)) .
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- If the arthimetic mean between a and b is (a^(n + 1) + b^(n + 1))/(a^(...
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- (x^-1+y^-1)xy=
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- (a^0)^0=
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- (a^n/a^m)^(m+n)xx(a^l/a^n)^(n+l)xx(a^m/a^l)^(l+m)=
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- (x^(3//4)*sqrty^-4)/(y^2*sqrtx^-3)xx(y^3sqrtx^9//2)/(y^-2sqrtx^9)=
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- 9^x+9^(x-1)=90 then x =
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