System performed pressure volume work wh...

System performed pressure volume work when in between system and surrounding there is

difference in temperature

difference in volume

difference in pressure

difference in internal energy

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Define system and surrounding.

In a process, the value of the change in entropy of the system and its surroundings are x and -y J*K^(-1) . If xgty, then will the process be spontaneous?

Assuming the system performs only pressure-volume work, show that heat evolved by a closed systemm at constant pressure is equal to the decrease in its enthalpy.

If the change in entropy of reversible isothermal expansion of 1 mol of an ideal gas is 9.135 " J mol"^(-1). K^(-1) , what will be the entropy change of the surroundings and universe ? If the above expansion of gas is allowed to occur against zero pressure, what will be the entropy change of the system and surroundings ?

Assuming the system performs only pressure-volume work, show that heat absorbed by a closed system at constant volume is equal to the increase in its internal energy.

For a process occurring in a closed system, DeltaU=q . If only pressure-volume work is performed by the system then which type of process is this?

There occurs no exchange of heat between a system and its surroundings in an adiabatic process. So, the change in entropy of the system is zero in this process. Justify the statement.

In a reversible process, if changes in entropy of the system and its surroundings are DeltaS_(1) & DeltaS_(2) respectively, then-

Among pressure of the system and the surroundings, which one is represented by 'P' in the equation H=U+PV ? What would be the change in enthalpy for the reaction A_(2)(s)+B_(2)(g) to 2AB(g) ?

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