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The solubility product of Hg2l2 is equal...

The solubility product of `Hg_2l_2` is equal to -

A

`[Hg^+][l^-]`

B

`[Hg^(+2)][l^-]`

C

`[Hg_2^(2+)][l^-]^2`

D

`[Hg^+]^(-2)[l^-]^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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