Calculate the number of oxygen atoms in 88 g `CO_2` What would be the mass of CO having the same number of oxygen atoms ?

Explanation

No. of O-atom in 88 g `CO_2` = `"No of moles" xx N_A xx2`
`88/44 xx6.023 xx 10^23 xx 2 = 2.40 xx 10^24`
Now, 28 g CO contains `6.023 XX 10^23` no. of O-atoms
Mass of CO containing `2.40 xx 10^24 g` no. of O-atoms.
`28/(6.02 xx 10^23) xx 2.40 xx 10^24 g = 112 g`