Home
Class 11
CHEMISTRY
The total number of protons in 10 g of c...

The total number of protons in 10 g of calcium carbonate is `(N_0 = 6.023 xx 10^23)`

A

`3.01 xx 10^24`

B

`4.06 xx 10^24`

C

`2.01 xx 10^24`

D

`3.02 xx 10^24`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN

    PATHFINDER|Exercise QUESTION BANK|77 Videos

  • MOLE AND STOICHIOMETRY-II

    PATHFINDER|Exercise QUESTION BANK|178 Videos

Similar Questions

Explore conceptually related problems

The total number of turns for a toroid carrying current 100mA is.1500. If 10 xx 10^-2 m be the diameter of the toroid of length 0.5m, then find out the value of magnetic induction at the centre of the toroid.

Density of Li is 0.53"g cm"^(-3) . The edge length of Li is 3.5Å . Find the number of Li atoms in a unit cell (N_(0)=06.023xx10^(23),M=6.94) .

The initial number of radioactive atoms in a radioactive sample is N_0 . If after time t the number of becomes N, then N=N_0e^(-lambdat) , where lambda is known as the decay constant of the element. The time in which the number of radioactive atoms becomes half of its initial number is called the half-life (T) of the element. The time in which the number of atoms falls to 1/e times of its initial number is the mean life (tau) of the element. The product lambdaN is the activity (A) of the radioactive sample when the number of atoms is N. The SI unit of activity is bequerel (Bq)' where 1 Bq = 1 decay. s^(-1) . The half-life of Iodine-131 is 8 d. What is the activity (in Bq) of 1 g of Iodine? (A) 2.3xx10^15 (B) 4.6xx10^15 (C) 6.9xx10^15 (D) 9.2xx10^15

The initial number of radioactive atoms in a radioactive sample is N_0 . If after time t the number of becomes N, then N=N_0e^(-lambdat) , where lambda is known as the decay constant of the element. The time in which the number of radioactive atoms becomes half of its initial number is called the half-life (T) of the element. The time in which the number of atoms falls to 1/e times of its initial number is the mean life (tau) of the element. The product lambdaN is the activity (A) of the radioactive sample when the number of atoms is N. The SI unit of activity is bequerel (Bq)' where 1 Bq = 1 decay. s^(-1) , The half-life of Iodine-131 is 8d. Its decay constant (in SI) is - (A) 10^(-6) (B) 1.45xx10^(-6) (C) 2xx10^(-6) (D) 2.9xx10^(-6)

The initial number of radioactive atoms in a radioactive sample is N_0 . If after time t the number of becomes N, then N=N_0e^(-lambdat) , where lambda is known as the decay constant of the element. The time in which the number of radioactive atoms becomes half of its initial number is called the half-life (T) of the element. The time in which the number of atoms falls to 1/e times of its initial number is the mean life (tau) of the element. The product lambdaN is the activity (A) of the radioactive sample when the number of atoms is N. The SI unit of activity is bequerel (Bq)' where 1 Bq = 1 decay. s^(-1) , and Avogadro's number, N=6.023xx10^23 What is the ratio of activity of same amount of sodium-24 to that of iodine-131? [half life of sodium-24 is 15h.] (A) 1/70 (B) 1/7 (C) 7 (D) 70

The initial number of radioactive atoms in a radioactive sample is N_0 . If after time t the number of becomes N, then N=N_0e^(-lambdat) , where lambda is known as the decay constant of the element. The time in which the number of radioactive atoms becomes half of its initial number is called the half-life (T) of the element. The time in which the number of atoms falls to 1/e times of its initial number is the mean life (tau) of the element. The product lambdaN is the activity (A) of the radioactive sample when the number of atoms is N. The SI unit of activity is bequerel (Bq)' where 1 Bq = 1 decay. s^(-1) . The half-life of Iodine-131 is 8 d. Its mean life (in SI) is - (A) 4.79xx10^5 s. (B) 6.912xx10^5 s. (C) 9.974 xx 10^5 s. (D) 22.96xx10^5 s.

The value of avagadros number is 6.022xx10^(23) .

The velocity of a proton is 10^3 ms^-1 and mass of it is 1.67 xx10^(-27) kg , determine the Wavelength of that proton particle in nanometer unit (h = 6.63 xx 10^(-34) Js)

Is the statement correct or incorrect- 35.5g of chlorine contains 6.022xx10^(23) molecules?

Is the statement correct or incorrect- 35.5g of chlorine contains 6.022xx10^(23) molecules?

PATHFINDER-MOLE AND STOICHIOMETRY-I-QUESTION BANK
  1. The maximum number of molecules are present in

    Text Solution

    |

  2. How many moles of magnesium phosphate, Mg3(PO4)2 will contain 0.25 mol...

    Text Solution

    |

  3. The total number of protons in 10 g of calcium carbonate is (N0 = 6.02...

    Text Solution

    |

  4. The number of hydrogen atoms present in 25.6 g of sucrose (C12H22O11) ...

    Text Solution

    |

  5. A compound used in making nylon contains 48.3% oxygen. There are four ...

    Text Solution

    |

  6. Given that the abundance of isotopes ,^54Fe, ^56Fe and " ^57Fe are ...

    Text Solution

    |

  7. An unknown element forms an oxide. What will be the equivalent weight ...

    Text Solution

    |

  8. 1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The...

    Text Solution

    |

  9. Equivalent weight of a bivalent metal is 37.2. The molecular weight of...

    Text Solution

    |

  10. A sample of H2SO4 (density 1.787 g mL^(-1)) is labelled as 86% by weig...

    Text Solution

    |

  11. A 3M solution of Na2S2O3 (Relative Formula Mass = 158) has density of ...

    Text Solution

    |

  12. What is the empirical formula of an oxide of vanadium, if 2,74 gm, of ...

    Text Solution

    |

  13. A gaseous compound is composed of 85.7% by mass of carbon and 14.3% by...

    Text Solution

    |

  14. 0.1 mole of a carbohydrate with empirical formula CH2O contain 1 g of ...

    Text Solution

    |

  15. One hydrated salt Na2CO3.xH2O undergoes 63% loss in mass on heating an...

    Text Solution

    |

  16. 2 gm of a sample contains mixture of SiO2 and FE2O3. The sample on ver...

    Text Solution

    |

  17. Calculated the weight of MnO2 required to produce 1.78 litre of Cl2 at...

    Text Solution

    |

  18. The volume of oxygen necessary for the complete combustion of 20 L of ...

    Text Solution

    |

  19. 2.76 g of silver carbonate on being strongly heated yield a residue we...

    Text Solution

    |

  20. A mixture of NH4NO3 and (NH4)2HPO4 contain 30.4 mass percentage of nit...

    Text Solution

    |