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100 mL of 0.06 M Ca(NO3)2 is added to 50...

100 mL of 0.06 M `Ca(NO_3)_2` is added to 50 mL of 0.06 M `Na_2C_2O_4` After the reaction is complete

A

0,003 moles of calcium oxalate will get precipitated

B

0.003 M of `Ca^(++)` will remain in excess

C

`Na_2C_2O_4` is limiting reagent

D

`Ca(NO_3)_2`is excess reagent

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The correct Answer is:
A, B, C, D
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