Home
Class 11
CHEMISTRY
If the value of Avogadro number is 6.023...

If the value of Avogadro number is `6.023 xx 10^23 mol^(-1)` and the value of Boltzmann constant is `1.380 xx 10 ^(-23) J K^(-1)`, then the number of significant digits in the calculated value of the universal gas constant is

Text Solution

Verified by Experts

The correct Answer is:
6
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN

    PATHFINDER|Exercise QUESTION BANK|77 Videos

  • MOLE AND STOICHIOMETRY-II

    PATHFINDER|Exercise QUESTION BANK|178 Videos

Similar Questions

Explore conceptually related problems

The value of avagadros number is 6.022xx10^(23) .

Calculate the value of universal gas constant in CGS unit.

The value of Avogadro number is 6 .022 xx 10^23 . How many significant figures are there in this number.

The Avogadro number is 6.022 xx10^(23) . How many significant figures are there ?

If Avogadro number N_A is changed from 6.022 xx 10^23 mol^(-1) to 6.022 xx 10^20 mol^(-1) this would change the mass of one mole of carbon

If Avogadro number N_A is changed from 6.022 xx 10^23 mol^(-1) to 6.022 xx 10^20 mol^(-1) this would change the definiton of mass in units of grams

If Avogadro number N_A is changed from 6.022 xx 10^23 mol^(-1) to 6.022 xx 10^20 mol^(-1) this would change the ratio of chemical species to each other in a balanced equation

Given the value of Rydberg constant is 10^7m^(-1) , the wave number of the last line of the Balmer series in hydrogen spectrum will be

At 27^@C the average thermal energy of He atom is [K = 1.38 xx 10^-23 J]

If Avogadro number is changed from 6.022xx10^(23)mol^(-1) to 6.022xx10^(20)mol^(-1) this would change-

PATHFINDER-MOLE AND STOICHIOMETRY-I-QUESTION BANK
  1. Number of molecules in 1 litre of water is close to

    Text Solution

    |

  2. The percentage of N2 in urea is about

    Text Solution

    |

  3. The V.D of a gas is 11.2 . The volume occupied by one gram of the gas ...

    Text Solution

    |

  4. For 14 g of CO the wrong statement is

    Text Solution

    |

  5. The weight of 112 mL of oxygen at NTP is

    Text Solution

    |

  6. The oxygen obtained from 72 kg of water is

    Text Solution

    |

  7. One mole of CH4 contains

    Text Solution

    |

  8. The total number of electrons in 18 mL of water (density = 1 g . mL^(-...

    Text Solution

    |

  9. The equivalent mass of a certain bivalent metal is 20 . The molecular ...

    Text Solution

    |

  10. A compound has the molecular formula X4O6 If 10 g of X4O6 has 5.72 g X...

    Text Solution

    |

  11. 5 moles of Ba(OH)2 are treated with excess of CO2 How much BaCO3will b...

    Text Solution

    |

  12. A metal oxide has the formula A2O3 It can be reduced by hydrogen to gi...

    Text Solution

    |

  13. How many moles of magnesium phosphate, Mg3(PO4)2 will contain 0.25 mol...

    Text Solution

    |

  14. The number of sodium atom in 2 moles of sodium ferrocyanide is

    Text Solution

    |

  15. Arrange the following in order of increasing mass (atomic mass, O = 16...

    Text Solution

    |

  16. 20.0 kg of N2 (g) and 3.0 kg of H2(g) are mixed to produce NH3(g) form...

    Text Solution

    |

  17. Stoichiometric ratio of sodium dihydrogen orthophosphate and sodium hy...

    Text Solution

    |

  18. Which of the following sets of compounds correctly illustrate the law ...

    Text Solution

    |

  19. If the value of Avogadro number is 6.023 xx 10^23 mol^(-1) and the val...

    Text Solution

    |

  20. A compound H2X with molar weight of 80 g is dissolved in a solvent hav...

    Text Solution

    |