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Quantum mechanical calcuations show that...

Quantum mechanical calcuations show that mathematical mixing of certain combinaaation of orbitals in a given atom forms hybrid orbitals. The spatial orientations of these new orbitals lead to more stable bonds and are consistent with the observed molecular shapes . The process of orbital mixing is called hybridization and the new atomic orbitals are called hybrid orbitals.-
Conditions
(i) The no. of hybrid orbitals equal the number of atomic orbitalsmixed.
(ii)The type of hybrid orbitals obtained varies with the type of atomic orbitals mixed.
Rules to determine hybrid orbitals.
Method i:Count no .of atoms directiy attached to central atom + lone pairs+single electrons.
Method II: Count `sigma`- bonds+co-ordinate bonds+ lone pair+single electrons.
If the number comes one to be
`2 implies sp` `5 implies sp^3d/dsp^3`
`3 implies sp^2` `6 implies sp^3d^2/d^2sp^3`
`4 implies sp^3/dsp^2` `7 implies sp^3d^3`
Answer the following questions based on above passage :
Hybrid states of Xe in `XeF_2, XeF_4` and `XeF_6` respectively are :

A

`sp^2, Sp^3d, sp^3d^2`

B

`sp^3d, sp^3d^2, sp^3d^3`

C

`sp^3d^2, sp^3d, sp^3d^3`

D

`sp^2, sp^3, sp^3d`

Text Solution

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The correct Answer is:
B
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Quantum mechanical calcuations show that mathematical mixing of certain combinaaation of orbitals in a given atom forms hybrid orbitals. The spatial orientations of these new orbitals lead to more stable bonds and are consistent with the observed molecular shapes . The process of orbital mixing is called hybridization and the new atomic orbitals are called hybrid orbitals.- Conditions (i) The no. of hybrid orbitals equal the number of atomic orbitalsmixed. (ii)The type of hybrid orbitals obtained varies with the type of atomic orbitals mixed. Rules to determine hybrid orbitals. Method i:Count no .of atoms directiy attached to central atom + lone pairs+single electrons. Method II: Count sigma - bonds+co-ordinate bonds+ lone pair+single electrons. If the number comes one to be 2 implies sp 5 implies sp^3d/dsp^3 3 implies sp^2 6 implies sp^3d^2/d^2sp^3 4 implies sp^3/dsp^2 7 implies sp^3d^3 Answer the following questions based on above passage : Phosphorous pentachloride in gaseous state exists as a momomer. In solid state, it exists as PCl_5^+. PCl_6^- ions. The hybrid state of P atom in PCl_5 is sp^3d . The hybrid state of P atoms in PCl_4^+ and PCl_6^- will be respectively

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