https://d10lpgp6xz60nq.cloudfront.net/physics_images/PAT_CHE_0XI_B05_C11_E01_132_Q01.png

Match column I with column II: ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BIO_XI_C18_E01_003_Q01.png" width="80%"gt

Match column I with column II ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BIO_XI_C16_E01_002_Q01.png" width="80%"gt

Match Column I with Column II: ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BIO_XI_C20_E01_010_Q01.png" width="80%"gt

Match the followings (column I with column II) ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BIO_XI_C03_E01_011_Q01.png" width="80%"gt

Match the following: ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BIO_XI_C04_E01_014_Q01.png" width="80%"gt

Match the terms in column I with those in column II: ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BIO_XI_C07_E01_011_Q01.png" width="80%"gt

Match the items of column I with those of column II: ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BIO_XI_C19_E01_011_S01.png" width="80%"gt

Match the items given in column A and B: ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_BIO_XII_C16_E01_004_Q01.png" width="80%"gt

ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CEN_ALG_DPP_4_2_E01_232_Q01.png" width="80%"gt Let ABCD is a unit square and each side of the square is divided in the ratio alpha : (1-alpha) (0 lt alpha lt 1) . These points are connected to obtain another square. The sides of new square are divided in the ratio alpha : (1-alpha) and points are joined to obtain another square. The process is continued idefinitely. Let a_(n) denote the length of side and A_(n) the area of the n^(th) square The value of alpha for which sum_(n=1)^(oo)A_(n)=(8)/(3) is/are

If the positive integers are written in a triangular array as shown below, ltimg src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CEN_ALG_DPP_4_4_E01_252_Q01.png" width="80%"gt then the row in which the number 2010 will be, is