An organic compound `E(C_5H_8)` on hydrogenation gives compound `F(C_5H_12)` compound E on ozonolysis gives formaldehyde and 2-keto propanal deduce the structure of compound E

An optically active compound having molecular formula C_(8)H_(16) on ozonolysis gives acetone as one of the products. The structure of the compound is

An organic compound 'A' (C_(4)H_(10)O) is optically active. On mild oxidation, it gives a compound 'B' (C_(4)H_(8)O) but upon vigorous oxidation, it gives another compound 'C' (C_(3)H_(6)O_(2)) . The compound 'C' along with 'D' are also formed from 'B' by reacting with iodine in the presence of alkali. Deduce the structures of 'A', 'B', 'C' and 'D' .

Identify the Compound which on Ozonolysis gives Methanal and propanal. Write with example Markonikov's rule.

A compound having molecular formula C_(8)H_(18) can form only one monobromo derivative. Draw the structure of the compound.

Compound A treated with NaNH_2 followed by CH_3CH_2Br gave compound B. Partial hydrogenation of compound B produced compound C, which on ozonolysis gave a carbonyl contpound D. (C_3H_2O) . Compound D did not respond to iodofom test with I_2//KI and NaOH. Find out the structures of A, B, C & D.

A compound 'X' (C_(2)H_(4)O) on oxidation gives 'Y' (C_(2)H_(4)O_(2)) . The compound 'X' undergoes haloform reaction. Write the structure of 'X' and 'Y'. Name the product when 'X' is treated with NaOH .

Compound (A) C_(6)H_(12)O_(2) on reduction with LiAlH_(4) yields two compounds B and C. The compound (B) on oxidation gave (D) which on treatment with aqueous alkali and subsequent heating furnished E. The latter on catalytic hydrogenation gave (C). Compound (D) on oxidation gave monobasic acid (molecular formula weight = 60). Deduce the structure of (A), (B), (C), (D) and (E).

A hydrocarbon having the molecular formula C_6H_(10) , on catalytic hydrogenation absorbs one mole of H_2 . The product obtained on ozonolysis of the compound is OHC""CH_2CH_2CH_2CH_2CHO . Determine the structure of the compound.