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When 0.087 mol of NO and 0.0437 mal of B...

When 0.087 mol of NO and 0.0437 mal of `Br_2` are mixed in a closed container at constant temperature, 0.0518 mol of NOBr is obtained at equilibrium. The equilibrium amount of NO and `Br_2` are :

A

NO = 0.352 mol, `Br_2` = 0.0178 mol

B

NO = 0.352 mol, `Br_2` = 0.178 mol

C

NO = 0.0352 mol, `Br_2` = 0.0178 mol

D

NO = 0.3052 mol, `Br_2` = 0.0178 mol

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The correct Answer is:
D
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