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A flask containing 0.06 mole of F2(g) is...

A flask containing 0.06 mole of `F_2(g)` is allowed to equilibrate with F(g) at 1000 K. If the total pressure of the gases at equilibrium is 2.07 bar, calculate mole fraction of each gases at equilibrium.
Given `F_2(g) iff 2F(g), K_p (1000K) = 9.5 xx 10^-3`

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`x_(F_2) = 0.933,x_F = 0.064`
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