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H2O+H3PO4iffH(H3O)^++H2(PO4)^-, pK1=2.15...

`H_2O+H_3PO_4iffH_(H_3O)^++H_2(PO_4)^-, pK_1=2.15`
`H_2O+H_2PO_4^-iffH_(H_3O)^++H(PO_4)^(2-) pK_2 =7.20`
Hence, pH of 0.01 M `NaH_2PO_4` is

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