COD value of a water sample is 40 ppm, Calculate the amount of acidified `K_2Cr_2O_7` required to oxidise the organic matter present in 500 ml of that water sample.

COD of a water sample is 8 ppm, Calculate the weight of acidified K_2Cr_2O_7 required to oxidise the matter present in one litre of water sample.

COD of water sample is 8ppm the weight of acidified K_2Cr_2O_7 required to oxidise the organic matter present in one liter of water sample is

10^-3 gm equivalents of K_2Cr_2O_7 in 50% H_2SO_4 is needed to oxidise all the organic matter present in 1 liter of water. Then COD of water is

DO value of a water sample is 6 ppm. Calculate the weight of dissolved oxygen present in 100 Kg of water sample.

What amount of K_(2)Cr_(2)O_(7) (in mmol) is required to oxidise 24ml 0.05 M Mohr's salt?

What happens when ethylbenzene is heated with acidified K_(2)Cr_(2)O_(7) ?

What volume of 2 N K_2Cr_2O_7 solution is required to oxidise 0.81 g of H_2S in acidic medium?

100 mt of a sample of water requires 0.98mg of K_2Cr_2O_7 (M.W=294) in presence of the H_2SO_4 for the oxidation of dissolved organic matter in it. The C.O.D of the water is

V ml solution of Fe^(2+) can be oxidised by 60 ml of KMnO_4 in acidic medium. What will be the volume of K_2Cr_2O_7 required to oxidise V ml of the same Fe^(2+) solution in an acidic medium ? Consider the molarity of KMnO_4 and K_2Cr_2O_7 to be the same.