`360cm` of `CH_(4)` gas diffused through porous membrane in `15` minutes,under similar conditions, `120cm^(3)` of another gas diffused in `10` minutes.Find the molar mass of the gas.

180ml of hydrogen diffuses through a porous membrane in 15 minutes while 120 ml of SO_(2) under identical conditions diffused in 20 minutes. What is the molecular mass of the hydrocarbon ?

180cm^(3) of a hydrocarbon diffuses in 15 min, while under the same conditions, 120cm^(3) of sulphur dioxide diffuse in 20 min. If the molecular mass of SO_(2) is 64, what is the molecular formula of the hydrocarbon?

The time taken for a certain volume of gas to diffuse through a small hole was 2 min . Under similar conditions an equal volume of oxygen took 5.65 minute to pass. The molecular mass of the gas is

20L of SO_(2) diffuse through a porous partition in 60 seconds. Volume of O_(2) diffuse under similar conditions in 30 secodns will be:

An unknown gas diffuses four times as quickly as oxygen. Calculate the molar mass of the gas.

20 dm^(3) of SO_(2) diffuse through a porous partition in 60 s. what volume of O_(2) will diffuse under similar conditions in 30 s ?