Decrease in vapour pressure of water by adding 5 mol sucrose or 5 mol urea to one kg of water is same why?

Vapour pressure of water at 293 kis 17.535 mm Hg. Calcualte the vapour pressure of water at 293 K when 25 g of glucose is dissolved in 450 g of water.

A solution containing 30g of non-volatile solute exactly in 90g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate: molar mass of the solute

The vapour pressure of water is 12.3 kPa at 300 K. Calculate vapour pressure of 1 molal solution of a non-volatile solute in it.

100 g of liquid A (molar mass 140 g mol^-1) was dissolved in 1000g of liquid B (molar mass 180 g mol^-1) . The vapour pressure of pure liquid B was found to be 500 torr: Calculate the vapour pressure of pure liquid A and its vapour pressure in the solution if the total vapour pressure of the solution is 475 Torr.

Urea forms an ideal solution in water. Determine the vapour pressure of an aqueous solution containing 10% by mass of urea at 40^@C .[Vapour pressure of water at 40^@C = 55.3mm of Hg ]

Urea [NH_2)_2CO] forms an ideal solution in water. Calculate the vapour pressure of an aqueous solution containing 5% by mass of urea at 298K. At 298K, vapour pressure of water is 23.75 mm Hg.

Explain why Vapour pressure of a liquid decreases when a non-volatile solute is added to it.

A solution containing 30 g of non-volatile solute exactly in 90g of water has a vapour presure of 2.8K Pa at 298K. Further 10g of water is added to this solution. The new vapour pressure becomes 2.9K Pa at 298K. Calculate Vapour presure of water at 298K

What is the mass of 0.5 mole of water molecules?

A solution containing 30 g of non-volatile solute exactly in 90g of water has a vapour presure of 2.8K Pa at 298K. Further 10g of water is added to this solution. The new vapour pressure becomes 2.9K Pa at 298K. Calculate 298K. The molar mass of the solute