2g of a non-electrolyte solute dissolved in 100g of benzene lowered the freezing point of benzene by 0.40 K. find the molar mass of the solute.

1.0 g of a nonelectrolyte solute dissolved in 50g of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant of benzene is 5.12 K kg mol. Find the molar mass of the solute.

A solution is prepared by dissolving 1.25g of oil wintergreen (methyl salicylate) in 99.0g of benzene has or boiling point of 80.31^@C . Determine the molar mass of this compound. (bp of pure benzene, 80.10^@C and K_b for benzene, 2.53^@Ckg mol -1 )

Calculate the mass of compound ( molar mass = 256 g mol^(-1) ) to be dissolved in 75 g of benzene to lower its freezing point by 0.48 K (Kf= 5.12 K kg mol^(-1)) .

An aqueous solution of 2 percent non-volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molecular mass of the solute?

What mass of NaCl (molar mass= 58.5g mol^-1) must be dissolved in 65g of water to lower the freezing point by 7.5^@C ? The freezing point depression constant, K_f for water is 1.86 K kg mol^-1 . Assume vant Hoff factor for NaCl is 1.87.

Two elements A and B form compounds having formula AB_2 and AB_4 . When dissolved in 20 g of benzene (C_6H_6) , 1 g of AB_2 lowers the freezing point by 2.3 K whereas 1.0 g of AB_4 lowers it by 1.3 K. The molar depression constant for benzene is 5.1 K kg mol^-1 . Calculate atomic masses of A and B.

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 0.84 g in 100g of water at 298K. Calculate the freezing point of water in the solution. (K_f for water = 1.86 K kg mol^-1)

A 0.561 m solution of an unknown electrolyte depresses the freezing point of water by 2.93^@C . What is Vant Hoff factor for this electrolyte? The freezing point depression constant (K_f) for water is 1.86^@C Kg mol^-1 .

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 6.84g in 100g of water at 298K. Calculate the freezing point of the solution ( K_f for water, 1.86K Kgmol^-1 ).

A solution containing 30g of non-volatile solute exactly in 90g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. Calculate: molar mass of the solute