A 1 molal aquous solution of trichloroacetic acid `(C Cl_3COOH)` is heated to its boiling point. The solution has the boiling point of `100.18^@C`. Determine the Van't Hoff factor for the acid (`k_b` for water = 0.512)

Show that for dimerisation of benzoic acid in benzene solution, degree of association, = 2(1-i) where I = Van't Hoff factor.

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 0.84 g in 100g of water at 298K. Calculate the boiling point of water in the solution (K_b for water = 0.52 K kg mol^-1)

A solution is prepared by dissolving 1.25g of oil wintergreen (methyl salicylate) in 99.0g of benzene has or boiling point of 80.31^@C . Determine the molar mass of this compound. (bp of pure benzene, 80.10^@C and K_b for benzene, 2.53^@Ckg mol -1 )

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 6.84g in 100g of water at 298K. Calculate the boiling point of the solution. ( K_b for water, 0.52K mol^-1 )

1.8g of glucose (C_6H_12O_6) is dissolved in 100g of water in a beaker. At what temperature will water in the solution boil at 1.013 bar? Given boiling point of pure water at 1.013 bar is 373.15K and K_b for water is 0.052K mol^(-1) .

0.52g of glucose (C_6H_12O_6) is dissolved in 80.2g of water calculate the boiling point of the solution. ( K_b for water is 0.52 K kg mol^-1 ).

How is it that the elevation in boiling points of the following solutions in water are different? 0.1 M NaCl solution 0.1 M Sugar solution.

An electric heater takes 15 min to raise a certain quantity of water from 0°C to its boiling point.If it takes another 80 min to turn all water into steam ,find the latent heat of vaporsation of water.

A 0.1539 molal aqueous solution of canesugar (molar mass = 342g mol^-1) has a freezing point 271K. While the freezing point of pure water is 273.15k. What will be the freezing point of an aqueous solution, containing 5g of glucose (Mol mass = 180g mol^-1) per 100g of solution?

A solution of sucrose (molecular mass 342 u) is prepared by dissolving 0.84 g in 100g of water at 298K. Calculate the freezing point of water in the solution. (K_f for water = 1.86 K kg mol^-1)