The limiting molar conductances of sodium chloride, hydrochloric acid and sodium acetate are 126.45, 426.16 and `91.0 Scm^2mol^-1` respectively at 298K. Calculate the limiting molar conductance of acetic acid at 298K.

The molar conductances of NaCl, HCl and CH_3COONa at infinite dilution are 126.45, 426.16 and 91.0 Scm^2 mol^-1 , respectively at 25^@C , Calculate the moalr conductance of acetic acid at infinite dilution.

The conductivity of 0.20M solution of KCl at 298K is 0.0248 Scm-1 . Calculate its molar conductivity.

The conductivity of 0.20M solution of KCl at 298K is 0.0248 S//cm .Calculate its molar conductivity.

The conductivity of 0.20M solution of KCL at 298K is 0.0248Scm^-1 , Calculate its molar conductivity.

Conductivity of 0.00241 M acetic acid is 7.896xx10^-5 S cm^-1 .Calculate its molar conductivity and what is its dissociation constant?

The conductivity of 0.001M acetic acid is 4X10^(-2)S//m . Calculate the dissociation constant of acetic acid if lambda_m^@ for acetic acid is 390Scm^2mol^(-1) .

The molar conductivity of 0.025 mol L^-1 methanoic acid is 46.1 S cm^2 mol^-1 . Calculate its degree of dissociation and dissociation constant. Given lambda^@(H^+) = 349.6 S cm^2 mol^-1 abd lamda^@(HCOO-) = 54.6 S cm^2 mol .

Represent the cell with cell reaction- Zn(s)+2Ag^+(aq) rarr Zn^(2+) (aq)+2Ag(s) Calculate the emf of the cell at 298K if the molar concentraction of Ag^+ and Zn^(2+) ions in the half cwells are 0.10 mol dm^(-3) and 0.01 mol dm^(-3) respectively. Given that E^@ Ag^+//Ag= 0.80V and E^@Zn^(2+)//Zn=-0.76V,

Conductivity of 2.5xx10^(-4)M methanoic acid is 5.25xx10^(-5)Scm^(-1) . Calculate its molar conductivity and degree of dissociation (Given lambda^@(H^+)=349.5Scm^2mol^(-1) and lambda^@(HCOO)=50.5 Scm^2mol^(-1) )