A zinc rod is dipped in 0.1M `sol^` of `ZnSO_4`. The sald is 95% dissociated at this dilution at 298K. Calculate the electrode potential.
`(E_(Zn^(2+)//Zn)^@=-0.76V)`

When a metal rod C in dipped in an aquos soluion of a metal D (having conentration 1M for D^(2+) ion) at 25^@C the standard electrode potential are C^(2+)//C=-0.76 volts. D^(2+)D=+0.34 volts .

One half-cell in a voltaic cell is constructed from a silver wire dipped in silver nitrate solution of unknonw concentration. It other half cell consists of a zinc electrode dipping in 1.0M solution of Zn(NO_3)_2 . A voltage of 1.48V is measure for this cell. Use this information to calculate the concentration of silver nitrate solution used (E_(Zn^(2+)//Zn)^0=-0.76V,E_(Ag^+//Ag)^0=+0.80V)

The conductivity of 0.20M solution of KCL at 298K is 0.0248Scm^-1 , Calculate its molar conductivity.

The conductivity of 0.20M solution of KCl at 298K is 0.0248 Scm-1 . Calculate its molar conductivity.

A copper silver cell is set up. The copper ion concentration is 0.10M . The concentration of silver ion is not known. The cell potential when measured was 0.422V. Determine the concentration of silver ions in the cell. (Given) E_(Ag^(2+)//Ag)^@=+0.80V,E_(Cu^(2+)//Cu)^@=+0.34V

Which is a stronger reducing agent Zn or Fe? If E_(Zn^(2+)//Zn)^@ = -0.76V , and E_(Fe^(2+)//Fe = -0.44V

What is the effect of an increase in concentration of Zinc ions on the electrode potential of Zinc electrode for which E^@ equals -0.76V.

What is the effect of an increase in concentration of zinc ions on the electrode potential of zinc electrode for which E^@ equals to -0.76V.

An electric dipole consists of charges +2e and -2e separated by 0.78 nm. It is placed perpendicular to a field 3.4*10^6 NC^-1 . Calculate the torque on it.

Represent the cell with cell reaction- Zn(s)+2Ag^+(aq) rarr Zn^(2+) (aq)+2Ag(s) Calculate the emf of the cell at 298K if the molar concentraction of Ag^+ and Zn^(2+) ions in the half cwells are 0.10 mol dm^(-3) and 0.01 mol dm^(-3) respectively. Given that E^@ Ag^+//Ag= 0.80V and E^@Zn^(2+)//Zn=-0.76V,