A battery of e.m.f 2V and internal resistance `1Omega` is used to send a current through a potentiometer wire of length 200cm and resistance `4Omega`. What length of the wire will be required to balance a cell of e.m.f `1.08V?

A potentiometer wire is of length 10 m and has a total resistance of 18 ohm. It carries a current of 120 mA. What length of it will be necessary to balance a cell of emf 1.5 volt ?

Two cell of emf. 1.5v and 2 v and internal resistance 2 and 1Omega respectively have their negative terminal joined by a wire of 6Omega and positive terminal by another wire of 4Omega A third resistance of 8Omega connected mid point of these wire. Find the potential difference at the end of the third wire.

For a Common emitter emplifer the voltage across collector resistance 2kOmega is 2V. If the current amplification factor is 200 and base resistance is 1.5Omega , what is the inpur voltage?

A potentiometer wire of length 100 cm has a resistance of 10 ohm. It is connected in series with a resistance and a battery of emf 2V and of negligible internal resistance. A source of emf 10mV is balanced against a length of 40 cm of the potentiometer wire. What is the value of the external resistance?