What is internal resistance of a cell?

Draw the circuit diagram of the potentiometer to determine the internal resistance of a cell and briefly describe the procedure.

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10 Omega is connected in parallel to the cell, the balancing length changes to 60 cm. The internal resistance of the cell is

Give the experimental procedure to find out the internal resistance of a given cell using a potentiometer.

The potential difference between the terminals of a cell in open circuit is 2.2V. When it is connected through a resistance of 5 ohm , the P.D. falls to 1.8V. Find the internal resistance of the cell.

A cell can be balanced against 110 cm and 100 cm of potentiometer wire respectively when in open circuit and when short circuited through a resistance of 10 Omega . Find the internal resistance of the cell.

In a potentiometer experiment, it is found that no current passes through the galvanometer, when the terminals of a cell are connected across 50 cm of the potentiometer wire. If the cell is shunted by a resistance of 5 ohm, the balance point is found at 40 cm of the wire from the same end. Find the internal resistance of the cell.

What is Variable resistance?