The perimeter of a circular field is 660cm.A square-shaped portion of the field is demarcated in such a way that its four vertices lie on the outside boundary of the field.Find the area of the square-shaped region of the field.

The perimeter of a circular field is 242 m then the area of the field is

Work Problem on Geometry The perimeter of a rectangular field is 80 m. If the length of the field id decreased by 2m and breadth is increased by 3 m, then the area of the field is increased by 64 sq.m. Find the dimension of the field.

A circular plot has a perimeter of 660m . A plot in the shape of a square havinng its vertices on the circumference of the field. Calculate the area of the square field.

The length of a side of a square is 4 cm.A circle is drawn through the four vertices of the square.Find the area of the portions between the circle and the square.

There is a path of width 3.5 m around the circular field of diameter 70m. Find the area of the whole path.

In Fig.12.25,ABCD is a square of side 14 cm.with centres A,B,C and D,four circles are drawn such that each circle touch externally two of the remaining three circles.Find the area of the shaded region.

In Fig 13,ABCD is a square of side 5.6 cm.As shown in the figure,four circles are drawn with centres A,B,C and D respectively.Find the area of the shaded region in the diagram. (pi=22/7)

The diagonal of a quadrilateral shaped field is 24m and the perpendiculars dropped on it from the remaining opposite vertices are 8m and 13m.Find the area of the field.

A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope. Find the area of that part of the field in which the horse can graze and the increase in the grazing area if the rope were 10 m long instead of 5 m.

There is an agriculture field in the form of rectangle of length of 20 m and width 14 m. A 10 m deep well of diameter 7 cm is dug in a corner of the field and the earth taken out of the well is spread evenly over the remaining part of the field. Find the rise in its level.