If `0lexle2pi`,find `sin x/2,cos x/2 and tan x/2`when `tan x=-4/3`,lies in quadrant II.

Solve : tanx+tan2x+tan3x=0

Solve : tan^-1 2x+tan^-1 3x=pi/4

Find the value of cos theta and tan theta if sin theta =-3/5 and piltthetalt3pi/2

Simplify tan^(-1) [(a cos x -b sin x)/(b cos x +a sin x)] , if (a)/(b) tan x gt -1 .

Evaluate the follwings: int(cos2x)/(sin2x) dx

Find the value of tan ^2theta sin^2 theta+ sin^2 theta-tan^2theta-1 =0

Solve for x : 2 tan^-1 x+sec^-1 x=pi/2

Find the intervals in which f(x) = sin x - cos x , 0 lt x lt 2pi , is strictly increasing or strictly decreasing.