A charge +q is distributed over a thin ring of radius r with line charge density `lambda=qsin^2 theta//(pir)`. Note that the ring is in the x-y plane and `theta` is the angle made by `vecr` with the x axis. The work done by the electric force in displacing a point charge +Q from the center of the ring to infinity is

Options

A. equal to `qQ//2piepsilon_0r`
B. equal to `qQ//4piepsilon_0r`
C. equal to zero only if the path is a straight line perpendicular to the plane of the ring
D. equal to `qQ//8piepsilon_0r`