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A star initially has 10^40 deuterons. It...

A star initially has `10^40` deuterons. It produces energy via the processes `_1H^2+_1H^2rarr_1H^3+p` `_1H^2+_1H^3rarr_2He^4+n` The masses of the nuclei are as follows: `M(H^2)=2.014` amu' `M(p)=1.007` amu, `M(n)=1.008` amu, `M(He^4)=4.001` amu if the average power radiated by the star is `10^16W`, the deuteron supply of the star is exhausted in a time of the order of

A

`10^6 sec`

B

`10^8 sec`

C

`10^12 sec`

D

`10^16 sec`

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A star initially has 10^40 deuterons. It produces energy via the processes _1^2H+_1^2Hrarr_1^3H+p and _1^2H+_1^3Hrarr_2^4He+n . Where the masses of the nuclei are m( ^2H)=2.014 amu, m(p)=1.007 amu, m(n)=1.008 amu and m( ^4He)=4.001 amu. If the average power radiated by the star is 10^16 W , the deuteron supply of the star is exhausted in a time of the order of

A star initially has 10^(40) deuterons it product energy via the process _(1)H^(2) + _(1)H^(2) + rarr _(1) H^(3) + p. and _(1)H^(2) + _(1)H^(3) + rarr _(2) He^(4) + n If the deuteron supply of the average power radiated by the state is 10^(16) W , the deuteron supply of the state is exhausted in a time of the order of . The masses of the nuclei are as follows: M(H^(2)) = 2.014 amu, M(p) = 1.007 amu, M(n) = 1.008 amu, M(He^(4)) = 4.001 amu.

A star initially has 10^40 deuterons. It produces energy via the processes _1H^2+_1H^2rarr_1H^3+p and _1H^2+_1H^3rarr_2He^4+n . If the average power radiated by the star is 10^16 W, the deuteron supply of the star is exhausted in a time of the order of (a) 10^6s (b) 10^8s (c) 10^12s The masses of the nuclei are as follows M(H^2)=2.014 amu, M(n)=1.008 amu, M(p)=1.007 amu, M(He^4)=4.001 amu

The source of energy of stars is nuclear fusion. Fusion reaction occurs at very high temperature, about 10^(7) . Energy released in the process of fusion is due to mass defect. It is also called Q -value. Q = Delta mc^(2), Delta m = mass defect. A star has 10^(40) deutrons. It produes via the process ._(1)H^(2) + ._(1)H^(2) rarr ._(1)He^(3) + ._(1)H^(1) ._(1)H^(3) + ._(1)H^(3) rarr ._(2)He^(4) + ._(0)n^(1) If the average power radiated by the star is 10^(16) W , when the deutron supply of the star is exhausted in a time of the order of

Calculate the energy released in the following: ._(1)H^(2) + ._(1)H^(3) rarr ._(2)He^(4) + ._(0)n^(1) (Given masses : H^(2) = 2.014, H^(3) = 3.016, He = 4.003, n = 1.009 m_(u))

The process, ""_(1)H^(2) +""_(1)H^(3) to ""_(2)He^(4) +""_(0)n^(1) represents the types of reaction known as

The nuclear reaction .^2H+.^2H rarr .^4 He (mass of deuteron = 2.0141 a.m.u and mass of He = 4.0024 a.m.u ) is

Calculate the Q - value of the reaction ._(1)H^(2)+._(1)H^(2) rarr ._(1)H^(3)+._(1)H^(1) m(._(1)H^(2))=2.014103 "amu" m(._(1)H^(3))=3.016049 "amu" m(._(1H^(1))=1.007825 amu

The atomic masses of deuteron, helium, neutron are 2.014 amu, 3.017 amu and 1.008 amu respectively. On fusion of 0.5 kg of deuterium, ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(3) + ""_(0)n^(1) , the total energy released is

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