Home
Class 12
PHYSICS
A car,starting from rest, accelerates at...

A car,starting from rest, accelerates at the rate f through a distance s, then continuous at constant speed for time t and then decelerates at the rate `f/2` come to rest. If the total distance traversed is 5 s,then :

A

`s=1/4 ft^2`

B

`s=1/2 ft^2`

C

`s=1/6 ft^2`

D

`s=ft`

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOCK TEST 1

    KVPY PREVIOUS YEAR|Exercise EXERCISE|23 Videos

  • MOCK TEST 2

    KVPY PREVIOUS YEAR|Exercise EXERCISE|26 Videos

Similar Questions

Explore conceptually related problems

A car, starting from rest, accelerates at the rate (f) through a distance (S), then continues at constant speed for some time (t) and then decelerates at the rate f//2 to come to rest. If the total distance is 5 S , then prove that S=1/2/ ft^(@) .

A particle accelerates from rest at a constant rate for some time and attains a velocity of 8 m/sec. Afterwards it decelerates with the constant rate and comes to rest. If the total time taken is 4 sec, the distance travelled is

Knowledge Check

  • A car, starting from rest, accelerates at the rate f through a distance s, then continues at constant speed for time t and then decelerates at the rate f/ 2 to come to rest. If the total distance travelled is 15 s, then

    A
    `s = (1)/(72) ft^(2)`
    B
    `s = (1)/(36) ft^(2)`
    C
    `s = (1)/(2) ft^(2)`
    D
    `s = (1)/(4) ft^(2)`

  • A particle starts from rest accelerates at 2 m//s^2 for 10 s and then goes for constant speed for 30 s and then decelerates at 4 m//s^2 till it stops. What is the distance travelled by it.

    A
    750 m
    B
    800 m
    C
    700 m
    D
    850 m

  • A particle starts from rest, accelerates at 2(m)/(s^2) for 10 s and then goes for constant speed for 30 s and then decelerates at 4(m)/(s^2) . Till it stops. What is the distance travelled by it?

    A
    750 m
    B
    800 m
    C
    700 m
    D
    850 m

    • Similar Questions

    Explore conceptually related problems

    A car starting from rest is acceleration at constant rate until it attains a speed of 12 m/s. It moves with the constant speed 12 m/s for some time and then it is retarded at other constant rate until it comes to rest. Considering theta the car moves with constant speed for half of the time of total journey, what will be the average speed of the car for the whole journey (in m/s) ?

    A train accelerates from at the constant rate b for time t_(2) at a constant rate a and then it retards at the comes to rest. Find the ratio t_(1) // t_(2) .

    A car starts from rest and accelerates at uniform rate of 6 m s^(-2) for some time, then moves with constant speed for some time and retards at the same uniform rate and comes to rest. Total time for the journey is 24 s and average speed for journey is 20 m s^(-1) , How long does the car move with constant speed?

    A car accelerates from the rest at a constant rate alpha for sometime after which it decelerates at a constant rate of b to come to rest. If the total time of travel is t, then the maximum velocity reached in this interval is

    A train starts from rest and moves with uniform acceleration alpha for some time and acquires a velocity v it then moves with constant velocity for some time and then decelerates at rate beta and finally comes to rest at the next station. If L is distance between two stations then total time of travel is

    Home
    Profile