The binding energy of deuteron .1^2 H is...

The binding energy of deuteron `._1^2 H` is `1.112 MeV` per nucleon and an `alpha-`particle `._2^4 He` has a binding energy of `7.047 MeV` per nucleon. Then in the fusion reaction `._1^2H + ._1^2h rarr ._2^4 He + Q`, the energy `Q` released is.

1 MeV

11.9MeV

23.8MeV

931MeV

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[" The binding energy of deutron "(1H^(2))" is "1.15" MeV per nucleon and an alpha "],[" particle "(2He^(4))" has a binding energy of "7.1" MeV per nucleon.Then in the "],[" reaction "1H^(2)+1H^(2)rarr_(2)He^(4)+Q],[" The energy Q released in MeV is "]

The binding energies per nucleon for a deuteron and an alpha- particle are x_1 and x_2 respectively. What will be the energy Q released in the following reaction ? ._1H^2 + ._1H^2 rarr ._2He^4 + Q .

The binding energy of deuteron is 2.2 MeV and that of ._2^4 He is 28 MeV . If two deutrons are fused to form one ._2^4 He , then the energy released is

The binding energies per nucleon for a deuteron and an alpha -particle are x_(1) and x_(2) respectively. What will be the energy Q released in the following reaction? ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(4) + Q

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The binding energies of deutron (._(1)H^(2)) and alpha - particle (._(2) He ^(4)) are 1. 125 and 7.2 Me V // nucleon respectively . In the process ._(1)H^(2) + ._(1) H^(2) to ._(2) He^(4) Amount of energy transferred is which nucleus is more stable ?

The binding energy of deuteron is 2.2 MeV and that of ._(2)^(4)He is 28 MeV. If two deuterons are fused to form one ._(2)^(4)He , th n the energy released is

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