A proton when accelerated through a potential difference of V volt has a wavelength `lamda` associated with it. An alpha-particle in order to have the same `lamda` must be accelerated through a potential difference of

A proton, when accelerated through a potential differnece of V = 29.6 V, has a wavelength lambda associated with it. An alpha- particle, in order to have the same lambda , must be accelerated through a potential difference of how many volts?

A proton when accelerated through a p.d of V volt has wavelength lambda associated with it. An electron to have the same lambda must be accelerated through a p.d of

An alpha -particle when accelerated through a potential of V volt has a wavelength lambda associated with it, but if a proton in order to have same wavelength lambda by what potential difference it must be accelerated?

The de-Broglie wavelength associated with a material particlewhen it is accelerated through a potential difference of 150volt is 1A. The de-Broglie wavelength associated with the same particle when it is accelerated through a potential difference of 1350 V will be:

An electron is accelerated through a potential difference of V volit .Find th e de Broglie wavelength associated with electron.

The de-Broglie wavelength associated with a material particle when it is accelerated through a potential difference of 150V is 1Å. What will be the de-broglie wavelength associated with the same particle when it is accelerted through a potential difference of 1350V?

An electron is accelerated through a potential difference of V volt. It has a wavelength lambda associated with it. Through what potential difference an electron must be accelerated so that its de Broglie wavelength is the same as that of a proton? Take massof proton to be 1837 times larger than the mass of electron