A certain charge Q is divided at first into two parts, q and Q-q. later on the charges are placed at a certain distance. If he force of interaction between two charges is maximum, then

two charge +q and -q are situated at a certain distance. At the point exactly midway between them

A certain charge Q is divided into two parts q and Q-q , wheich are then separated by a cetain distance. What must q be in terms of Q to maximum the electrostatic repulsion between the two charges?

A certain charge Q is divided into two parts q and (Q–q). How should the charges Q and q be divided so that q and (Q–q) placed at a certain distance apart experience maximum electrostatic repulsion ?

A charge 'Q' is divided into two parts A and B the two parts are separated by a certain fixed distance. Find for what charges on A and B would the force between them be maximum and comment when the force is minimum.

A total charge Q is broken in two parts Q_(1) and Q_(2) and they are placed at a distance R from each other. The maximum force of repulsion between them will occur, when

A charge is divided into two charges q and (Q-q) .The value of q so that force between them is maximum is equal to

Two point charges A and B, having charges +Q and -Q respectively, are placed at certain distance apart and force acting between them is F, if 25% charge of A is transferred to B, then force between the charges becomes:

A charge Q is divided into two parts q_(1) and q_(2) such that they experience maximum force of repulsion when separated by certain distance. The ratio of Q,q_(1) and q_(2) is

A charge Q is divided into two parts of q and Q -q . If the coulomb repulsion between them when they are separated is to be maximum, the ratio of Q/q should be