A block of mass `m` is lying on a wedge having inclination angle `alpha = tan^(-1)((1)/(5))` wedge is moving with a constant acceleration `a = 2 ms^(-2)` The minimum value of coefficient of friction `mu` so that `m` remain stationary w.r.t. wedge is

A block of mass m resting on a wedge of angle theta as shown in the figure. The wedge is given an acceleration a. What is the minimum value of a so that the mass m falls freely ?

A uniform cylnder of radius r and radius of gyration is kept on a fixed wedge of inclination theta . When we push the wedge with a constant acceleration a, the cylinder rolls up the wedge. Find coefficient of friction between the cylinder and wedge.

A block of mass m is placed on a smooth inclined wedge ABC of inclination theta as shown in the figure. The wedge is given an acceleration a towards the right. The relation between a and theta for the block to remain stationary on the wedge is.

A block of mass m is placed on the rough incline of a wedge of mass M and inclination alpha to the horizontal. Calculate the maximum and minimum acceleration that can be imparted to the wedge so that the block may remain stationary relative to the wedge. The coefficient iof friction between the block and the wedge is mu .

The air of density rho and moving with a velocity v strikes perpendicular the inclined surface of area A and of a wedge kept on a horizontal surface. The mass of the wedge is m . Assuming the collisions to be perfectly inelastic, the minimum value of the coefficient of friction between the wedge and the ground so that the wedge does not move is (Assume mass of particles of air is negligible)

A block of mass 2 kg is kept on a smooth wedge of mass 3 kg and wedge is kept on a rough horizontal surface. A vertical force of 60 N is applied on the minimum coefficient of friction between the wedge and horizontal surface, so that wedge remains at rest during the motion of block on the wedge ?

A block of mass 1 kg is at rest relative to a smooth wedge moving leftwards with constant acceleration a = 5 m//s^(-2) .Let N be the normal reation between the block and the wedge . Then (g = 10 m//s^(-2))

A block of mass "5kg" is placed on a wedge having inclination of 37^(@) with the horizontal. Coefficient of friction between block and wedge is 0.8. Then select the correct statement.