Let `f(x)=[2x^3-6]`, where [x] is the greatest integer less than or equal to x. Then the number of points in (1,2) where f is discontinuous is

If f(x)=|x-1|-[x] , where [x] is the greatest integer less than or equal to x, then

Let f(x)=[x^(2)+1],([x] is the greatest integer less than or equal to x) . Ther

Let f(x)=[t a n x[cot x]],x [pi/(12),pi/(12)] , (where [.] denotes the greatest integer less than or equal tox ). Then the number of points, where f(x) is discontinuous is a. one b. zero c. three d. infinite

If f(x)=|x-1|-[x] (where [x] is greatest integer less than or equal to x ) then.

Let f(x)=[x^3 - 3], where [.] is the greatest integer function, then the number of points in the interval (1,2) where function is discontinuous is (A) 4 (B) 5 (C) 6 (D) 7

Let f(x)=[x^(2)]+[x+2]-8 , where [x] denotes the greater integer than or equal to x , then

Let f(x)=(x-[x])/(1+x-[x]), where [x] denotes the greatest integer less than or equal to x,then the range of f is

The function f(x)=x-[x]+cos x, where [x]= the greatest integer less than or equal to x is a

If [x]^(2)=[x+6] , where [x]= the greatest integer less than or equal to x, then x must be such that

Let f(x)=[cosx+ sin x], 0 lt x lt 2pi , where [x] denotes the greatest integer less than or equal to x. The number of points of discontinuity of f(x) is