The de-Brogile wavelength of a neutron at `927^(@)`C is `lamda`. What will be its wavelength at `27^(@)`C?

The de - Broglie wavelength of a neutron at 27 ^(@) C is lambda . What will be its wavelength at 927^(@) C ?

The de-Broglie wavelength of a neutron at 1327^@C is lambda . What will be its wavelength at 127^@C ?

The de-Broglie wavelength lamda

The de-Broglie wavelength of thermal neutrons at 27^(@) C will be

The de-broglie wavelength of neutron at 27^(@)C is lambda . The wavelength at 927^(@)C will be

The de Broglie wavelength of a thermal neutron at 927^circC is lamda . Its wavelength at 327^circC will be

De Broglie wavelength of 0.05 eV thermal neutron is

The de-Broglie wavelength of an electron is 4 Å . What is its momentum ?