A force `vecF=(3xy-5z)hatj+4zhatk` is applied on a particle. The work done by the force when the particle moves from point `(0, 0, 0)` to point `(2, 4, 0)` as shown in figure.

A force of vecF=2xhati+2hatj+3z^2hatk N is acting on a particle. Find the work done by this force in displacing the body from (1, 2, 3)m to (3, 6, 1)m .

A force (5y + 20) hatj displaces a particle from y=0 to y=10. Find work done by force

Force acting on a particle varies with x as shown in figure. Calculate the work done by the force as the particle moves from x = 0 to x = 6.0 m.

A force vecF = (2xhati+ 3hatj + 3z^2hatk) is acting on the particle of mass 2kg which is displaces from point A(2,3,0) to point B(3,2,1) . the work done by the force on the particle will be

A force of F=(0.5x+12)N acts on a particle. If x is in metre, calculate the work done by the force during the displacement of the particle from x = 0 to x = 4 m

Shown that work done by a conservative force on a particle moving between two points is path independent.

Calculate the work done to displace the particle from (1,2) to (4,5) .if vecF=4hati+3hatj

A force F=(3xhati+4hatj) Newton (where x is in metres) acts on a particle which moves from a position (2m, 3m) to (3m, 0m). Then the work done is