The least count of a stop watch is 0.2 second. The time of 20 oscillations of a pendulum is measured to be 25 seconds.The percentage error in the time period is

The least count of a stop watch is 0.2 s, The time of 20 oscillations of a pendulum is measured to be 25s. The percentage error in the time period is

The least count of a stop watch is 0.2 second. The time of 20 oscillations of a pendulum is measured to be 25 seconds. The maximum percentage error in this measurement is found to be 0.x%. What is the value of x?

The least count of a stop watch is (1//5)s . The time 20 oscillations of a pendulum is measured to be 25 s . The maximum percentage error in this measurement is

The least count of a stopwatch is 0.2 s. A student found the time of 25 oscillations of a simple pendulum to be 50 second. What will be the percentage error in the measurement of time?

The time period of a seconds pendulum is ______ s.

In an experiment of simple pendulum, time period measured was 50s for 25 vibrations when the length of the simple pendulum was taken to be 100cm . If the lest count of stop watch is 0.1s and that of metre scale is 0.1 cm , calculate the maximum possible percentage error in the measurement of value of g .

The time taken to complete 10 oscillations by a seconds pendulum is

The time period of an oscillating simple pendulum is given as T=2pisqrt((l)/(g)) where l is its length and is about 1m having 1mm accuracy. Its time period is 2s . The time for 100 oscillations is measured by a stopwatch having least count 0.1s . The percentage error in the measurement of g is