If `x^2+9y^2+25 z^2=x y z((15)/2+5/y+3/z),t h e n` `x ,y ,a n dz` are in H.P. b. `1/x ,1/y ,1/z` are in A.P. c. `x ,y ,z` are in G.P. d. `1/a+1/d=1/b=1/c`

If x^(2)+9y^(2)+25z^(2)=xyz((15)/(x)+(5)/(y)+(3)/(z)), then x,y, andz are in H.P.(1)/(x),(1)/(y),(1)/(z) are in A.P.c.x,y,z are in G.P.d.(1)/(a)+(1)/(d)=(1)/(b)=(1)/(c)

If a^x=b^y=c^z and a,b,c are in G.P. show that 1/x,1/y,1/z are in A.P.

If distinct numbers x,y,z are in G.P. and 1/(x+a),1/(y+a),1/(z+a) are in A.P., prove that a=y .

IF a,b,c are in G.P and a^(1/x)=b^(1/y)=c^(1/z) then x,y,z are in

If reciprocals of (x+y)/2,y, (y+z)/2 are in A.P., show that x,y,z are in G.P.

If y-z,2(y-a),y-x are in H.P. prove that x-a,y-a,z-a are in G.P.