The resistance of metal is given by `V = IR`, The voltage in the resistance is `V = (8 pm 0.5)V` and current in the resistance is `I = (2 +- 0.2)A`, the value fo resistance with its percentage error is

The resistance of a metal is given by R = V//I , where V is potential difference and I is current . In a circuit , the potential difference across resistance is V = ( 8 +- 0.5) V and current in resistance , I = ( 4 +- 0.2)A . What is the value of resistance with its percentage error?

In a circuit potential difference across resistence V = (4 +- 0.25)V and curent in resistence , f = (1 +- 0.1) what is the value of resistence with its percentage error

The voltage measured across resistance is V = (50 pm 0.1)V and current is I = ( 10 pm 0.2) . Find error in resistance

The resistance R= (V)/(I) , where V= (100+-5.0) V and I=(10+-0.2)A . Find the percentage error in R .

If potential V = 100 +- 0.5 Volt and current I = 10 +- 0.2 amp are given to us. Then what will be the value of resistance

A potential of V= (10 pm 0.1) volt is applied across a resistance of (5 pm 0.2) Omega . Find the volue of current within error limits.

If voltage V=(100pm5) V and current I=(10pm0.2) A, the percentage error in resistance R is

An ammeter of resistance 0.5Omega is connected in the usual way to a circuit which has a cell of emf 1.5 V and an internal resistance 2Omega and a resistor 8Omega . What is the percentage error in the reading of the ammeter?

The resistance R=(V)/(I) , whereV= 100pm5V and I=10pm0.2A . The pressure error in V is 5% and in I is 2%. What is the total percentage error in R?