The equation of four circles are `(x+-a)^2+(y+-a2=a^2` . The radius of a circle touching all the four circles is `(sqrt(2)+2)a` (b) `2sqrt(2)a` `(sqrt(2)+1)a` (d) `(2+sqrt(2))a`

The equation of four circles are (x+-a)^(2)+(y+-a^(2)=a^(2). The radius of a circle touching all the four circles is (sqrt(2)+2)a( b) 2sqrt(2)a(sqrt(2)+1)a(d)(2+sqrt(2))a

Four circles each with radius 2 touches the axes, then the radius of the largest circle touching all the four circles, is

Consider four circles (x+-1)^(2)+(y+-1)^(2)=1 Find the equation of the smaller circle touching these four circles.

Three equal circles each of radius r touch one another.The radius of the circle touching all the three given circles internally is (2+sqrt(3))r(b)((2+sqrt(3)))/(sqrt(3))r((2-sqrt(3)))/(sqrt(3))r(d)(2-sqrt(3))r

The equation of a circle is x^(2)+y^(2)=4. Find the center of the smallest circle touching the circle and the line x+y=5sqrt(2)

Four circles each with radius 2 touch both the axes then the radius of the largest circle touching all the four circles is

The radius of the circle touching the straight lines x-2y-1=0 and 3x-6y+7=0 is (A) 1/sqrt(2) (B) sqrt(5)/3 (C) sqrt(3) (D) sqrt(5)

The radius of the circle passing through the points (1, 2), (5, 2) and (5, -2) is : (A) 5sqrt(2) (B) 2sqrt(5) (C) 3sqrt(2) (D) 2sqrt(2)

Find the equation of the circle with: Centre (a,a) and radius sqrt(2)a